Monday, October 31, 2011

5.6

Screen_shot_2011-10-31_at_2
Screen_shot_2011-10-31_at_2

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5.6 Questions (Collins, p.107)

Notes:
ρfresh water = 1,000kg/m3 
g = 10N/kg 
1,000mbar = 1 bar = 100,000Pa 

Q5) ∆p = h × ρ × g 250000- 100000 = h x 1000 150000 = h x 1000 x 10 
150000/ 1000 = 15m 

Q6) ∆p = h × ρ × g 
∆p = 50 x 420 (0.42x 1000 to change it into kg/m3) x 1.4 
∆p = 294000Pa 
1,000mbar = 1 bar = 100,000Pa so 1,600mbar = 1.6 bar = 160,000Pa 
29,400+160,000 = 189,400Pa TOTAL PRESSURE = 189,400Pa or 189.4 kPa 

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5.6 Plenary 

· Which diver experiences the greatest pressure? 

∆p = h × ρ × g 
They both experience the same amount of pressure because the height is the same and we assume that the density and the gravitational field strength will be the same in the 2 places. so therefore the pressure must be the same.

5.6

5.6

07 October 2011

10:40
· 5.6 recall and use the relationship for pressure difference:

pressure difference = height × density × g

∆p = h × ρ × g

∆p = pressure of the fluid (N/m2 or Pa)

h = height of the fluid (m)

ρ = density of the fluid (kg/m3)

g = gravitational field strength (N/kg)

5.6 Demo - squirting water column

12 October 2011

07:24

[cid:image001.jpg@01CC94C6.C4A53AA0]
· The bottom hole squirts water the furthest
· Because the water at the bottom has the greatest pressure
· Because in the formula ∆p = h × ρ × g, ρ is constant, g is constant and h is large
· So ∆p = large

5.6 Questions

07 October 2011

11:53

Collins, p.107

[cid:image002.jpg@01CC94C6.C4A53AA0]

Notes:

ρfresh water = 1,000kg/m3

g = 10N/kg

1,000mbar = 1 bar = 100,000Pa

Q5) ∆p = h × ρ × g 250000- 100000 = h x 1000 150000 = h x 1000 x 10
150000/ 1000 = 15m

Q6) ∆p = h × ρ × g
∆p = 50 x 420 (0.42x 1000 to change it into kg/m3) x 1.4
∆p = 294000Pa
1,000mbar = 1 bar = 100,000Pa so 1,600mbar = 1.6 bar = 160,000Pa
29,400+160,000 = 189,400Pa TOTAL PRESSURE = 189,400Pa or 189.4 kPa


5.6 Plenary

12 October 2011

07:23
· Which diver experiences the greatest pressure?

[cid:image003.jpg@01CC94C6.C4A53AA0]

∆p = h × ρ × g
They both experience the same amount of pressure because the height is the same and we assume that the density and the gravitational field strength will be the same in the 2 places.

5.5

5.5

07 October 2011

10:40
· 5.5 understand that the pressure at a point in a gas or liquid which is at rest acts equally in all directions


5.5 Demo 1 - Magdeburg Hemispheres

12 October 2011

07:19
· Magdeburg Hemispheres

[cid:image001.jpg@01CC94C6.05BEAF40]
· The original experiment was done by using two teams of wild horses to try and pull the hemispheres apart
· And here are the horses I was talking about! http://www.youtube.com/watch?v=7bJkaFByiA0&feature=related

5.5 Demo 2 - Collapsing Bottle

12 October 2011

07:19

· Collapsing Bottle

[cid:image002.jpg@01CC94C6.05BEAF40]

Objective 5.4

5.4 Starter

07 October 2011

11:46
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[cid:image002.png@01CC94B8.E00F63A0]

5.4 Starter 2 explained

07 October 2011

09:04

>


· Your finger pushes on the pin and the pin pushes back on your finger
· N3L tells us that all these two forces are equal in size
· The pin pushes on the wall and the wall pushes back on the pin
· N3L tells us that all these two forces are also equal in size
· If the surface area is large then the force is spread over a large area and the pressure is low
· If the surface area is small then the force is spread over a small area and the pressure is high
· You would like the pressure on your finger to be low and the pressure on the wall to be high
· The other way round is painful!

5.4

07 October 2011

10:37
· 5.4 recall and use the relationship between pressure, force and area:

pressure = force / area

p = F / A

[cid:image004.png@01CC94B8.E00F63A0]

5.4 Pressure Questions

07 October 2011

11:47
· PFY p.91, Q.3 and 7.

[cid:image005.png@01CC94B8.E00F63A0]

3) p=F/A 100,000N=F/10 100,000 x 10 = 1,000,000 N

[cid:image006.png@01CC94B8.E00F63A0]


[cid:image008.jpg@01CC94BE.1EB1D610]

7a) p=F/A p= 500/5 P= 100N/ cm2

b) p= F/A 100= F/20 P= 2000N


[cid:image009.png@01CC94B8.E00F63A0]

Question 1) Inuits wear snow shoes because if you look at the relationship between p=F/A when the area decreases the pressure increases. for example- 12/6 (area) = 2 (pressure) but 12/3 (area) =4 (pressure)

So if there is a large surface area on the snow shoes the Inuits will not sink into the snow.

Question 2) Tractors have big tires because p= F/A. when the area increases the pressure decreases. If the tractors have small tires the pressure will increase and the tractor will sink into the ground.

animation - why a drawing pin works.swf Download this file

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Objective 5.4

Instructions for Objective 5.4

1. 5.4 Starter. Who’s telling the truth? Read the explanation underneath.

2. 5.4 Starter 2. Open the attached animation. Why does pushing a drawing pin into the wall not hurt your finger? (as long as you get the pin the right way round!) Read the explanation below.

3. 5.4. Watch the video clips. Learn the formula and units

4. 5.4 Pressure Question. Forward this e-mail to your blog. Type your answers under the questions.

5. 5.4 Written Questions. Type your answers under the questions.

6. Answers to steps 4 and 5 will be sent separately. Don’t look at them until you’ve done the work!

Best wishes,

Mr B

5.4 Starter

07 October 2011

11:46
[cid:image001.png@01CC94B8.E00F63A0]
[cid:image002.png@01CC94B8.E00F63A0]

5.4 Starter 2 explained

07 October 2011

09:04

>


· Your finger pushes on the pin and the pin pushes back on your finger
· N3L tells us that all these two forces are equal in size
· The pin pushes on the wall and the wall pushes back on the pin
· N3L tells us that all these two forces are also equal in size
· If the surface area is large then the force is spread over a large area and the pressure is low
· If the surface area is small then the force is spread over a small area and the pressure is high
· You would like the pressure on your finger to be low and the pressure on the wall to be high
· The other way round is painful!

5.4

07 October 2011

10:37
· 5.4 recall and use the relationship between pressure, force and area:

pressure = force / area

p = F / A

[cid:image004.png@01CC94B8.E00F63A0]

5.4 Pressure Questions

07 October 2011

11:47
· PFY p.91, Q.3 and 7.

[cid:image005.png@01CC94B8.E00F63A0]

3) p=F/A 100,000N=F/10 100,000 x 10 = 1,000,000 N

[cid:image006.png@01CC94B8.E00F63A0]


[cid:image008.jpg@01CC94BE.1EB1D610]

7a) p=F/A p= 500/5 P= 100N/ cm2

b) p= F/A 100= F/20 P= 2000N


[cid:image009.png@01CC94B8.E00F63A0]

Question 1) Inuits wear snow shoes because if you look at the relationship between p=F/A when the area decreases the pressure increases. for example- 12/6 (area) = 2 (pressure) but 12/3 (area) =4 (pressure) So if there is a large surface area on the snow shoes the Inuits will not sink into the snow.

Question 2) Tractors have big tires because p= F/A. when the area increases the pressure decreases. If the tractors have small tires the pressure will increase and the tractor will sink into the ground.

animation - why a drawing pin works.swf Download this file

Image001

Image002

Image004

Image005

Image006

Image009

Image008

Monday, October 10, 2011

5.2 Density Questions

5.2 Density Questions
04 October 2011
14:00
·         
PFY p.84, Q.1,2,3,5,6 and 9.
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1. D=m/v  D= 100/20  D=5 g/cm3

2. D= m/v  D= 40,000/5  D= 8000 kg/m3
3. D=m/v   6000=v/3    mass= 18000kg 

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5. V=l x w x h V= 2 x 4 x 5  V=40m3
6. D= m/v   4000= 20000/v  v= 5         

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9. Density x volume= mass  2.5 x 4 x 10 x 1.3 = 130kg

Density of an irregular solid

Method
1. Measure mass using a balance.
2. Measure volume by using the "displacement method (submerge solid in a "Eureka" can and collect the overflow in a measuring cylinder )
3. Calculate density (p=m/V)

Results
1. m = 4.5g
2. V = 2cm3
3. p=m/V = 4.5/2 = 2.25g/cm3 
= 2g/cm3

Density of Water

Method:
1. Measure mass of empty measuring cylinder using a balance.
2. Measure mass of liquid and measuring cylinder.
3. Subtract 1 from 2 to calculate the mass of the liquid.
4. Measure volume of liquid by using the measuring cylinder (Note: measure to the bottom of the meniscus)
5. Calculate density (p = m/V)
Results:
1. Mcylinder
= 58.5g
2.Mcylinder+liquid
= 83.2g
3.Mliquid 
= Mcylinder+liquid-Mcylinder = 83.2 - 58.5 = 24.8g
4.V=25ml = 25cm3
5.p=m/V = 24.8/25 = 0.992 = 1
(m= mass)

5.3 Plenary

Drag'n'Drop Density (in kg per m3).swf Download this file

Remember: 1g/cm3 = 1,000kg/m3

5.3

Density Practical - regular and irregular solids and liquids.ppt Download this file

· 5.3 describe how to determine density using direct measurements of mass and volume