5.6 07 October 2011 10:40
· 5.6 recall and use the relationship for pressure difference: pressure difference = height × density × g ∆p = h × ρ × g ∆p = pressure of the fluid (N/m2 or Pa) h = height of the fluid (m) ρ = density of the fluid (kg/m3) g = gravitational field strength (N/kg) 5.6 Demo - squirting water column 12 October 2011 07:24 [cid:image001.jpg@01CC94C6.C4A53AA0]
· The bottom hole squirts water the furthest
· Because the water at the bottom has the greatest pressure
· Because in the formula ∆p = h × ρ × g, ρ is constant, g is constant and h is large
· So ∆p = large 5.6 Questions 07 October 2011 11:53 Collins, p.107 [cid:image002.jpg@01CC94C6.C4A53AA0] Notes: ρfresh water = 1,000kg/m3 g = 10N/kg 1,000mbar = 1 bar = 100,000Pa Q5) ∆p = h × ρ × g 250000- 100000 = h x 1000 150000 = h x 1000 x 10
150000/ 1000 = 15m Q6) ∆p = h × ρ × g
∆p = 50 x 420 (0.42x 1000 to change it into kg/m3) x 1.4
∆p = 294000Pa
1,000mbar = 1 bar = 100,000Pa so 1,600mbar = 1.6 bar = 160,000Pa
29,400+160,000 = 189,400Pa TOTAL PRESSURE = 189,400Pa or 189.4 kPa
5.6 Plenary 12 October 2011 07:23
· Which diver experiences the greatest pressure? [cid:image003.jpg@01CC94C6.C4A53AA0] ∆p = h × ρ × g
They both experience the same amount of pressure because the height is the same and we assume that the density and the gravitational field strength will be the same in the 2 places.
· 5.6 recall and use the relationship for pressure difference: pressure difference = height × density × g ∆p = h × ρ × g ∆p = pressure of the fluid (N/m2 or Pa) h = height of the fluid (m) ρ = density of the fluid (kg/m3) g = gravitational field strength (N/kg) 5.6 Demo - squirting water column 12 October 2011 07:24 [cid:image001.jpg@01CC94C6.C4A53AA0]
· The bottom hole squirts water the furthest
· Because the water at the bottom has the greatest pressure
· Because in the formula ∆p = h × ρ × g, ρ is constant, g is constant and h is large
· So ∆p = large 5.6 Questions 07 October 2011 11:53 Collins, p.107 [cid:image002.jpg@01CC94C6.C4A53AA0] Notes: ρfresh water = 1,000kg/m3 g = 10N/kg 1,000mbar = 1 bar = 100,000Pa Q5) ∆p = h × ρ × g 250000- 100000 = h x 1000 150000 = h x 1000 x 10
150000/ 1000 = 15m Q6) ∆p = h × ρ × g
∆p = 50 x 420 (0.42x 1000 to change it into kg/m3) x 1.4
∆p = 294000Pa
1,000mbar = 1 bar = 100,000Pa so 1,600mbar = 1.6 bar = 160,000Pa
29,400+160,000 = 189,400Pa TOTAL PRESSURE = 189,400Pa or 189.4 kPa
5.6 Plenary 12 October 2011 07:23
· Which diver experiences the greatest pressure? [cid:image003.jpg@01CC94C6.C4A53AA0] ∆p = h × ρ × g
They both experience the same amount of pressure because the height is the same and we assume that the density and the gravitational field strength will be the same in the 2 places.
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